At certain temperature, $1.6$ % solution of an unknown substance is isotonic with $2.4$ % solution of urea. If both the solutions have the same solvent and both the solution have same density $1 g m / {c m}^{3}$ , what will be the molecular mass of unknown substance in $g m / m o l$ .
(Molecular mass of urea $60 g m / m o l$ )

30

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40

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80

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90

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Solution

The correct option is B $40$
Isotonic solutions have same osmotic pressure-
$π = i C R T$
$\Rightarrow π_{1} = π_{2}$

$C_{1} = C_{2}$
For the same type of solvent with same volume,
$n_{1} = n_{2}$

$\frac{1.6}{M} = \frac{2.4}{60}$
$M = 40$ g/ mol

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At certain temperature, 1.6% solution of an unknown substance is isotonic with 2.4% solution of urea. If both the solutions have the same solvent and both the solution have same density 1 gm/cm3, what will be the molecular mass of unknown substance in gm/mol.(Molecular mass of urea 60 gm/mol)

The correct option is B 40Isotonic solutions have same osmotic pressure-π=iCRT ⇒π1=π2C1=C2For the same type of solvent with same volume,n1=n21.6M=2.460M=40 g/ mol

The correct option is B $40$
Isotonic solutions have same osmotic pressure-
$π = i C R T$
$\Rightarrow π_{1} = π_{2}$

$C_{1} = C_{2}$
For the same type of solvent with same volume,
$n_{1} = n_{2}$

$\frac{1.6}{M} = \frac{2.4}{60}$
$M = 40$ g/ mol