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Osmotic Pressure

At certain te...

Question

At certain temperature, a $5.12 %$ solution of cane sugar is isotonic with a $0.9 %$ solution of unknown solute. The molar mass of the solute is:

A

60

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B

46.17

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C

120

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D

90

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Solution

The correct option is A 60
Molar mass of sugarcane= $342$
Since isotonic solution

$∴ \frac{M o l a r m a s s o f s u g a r c a n e}{m a s s % o f s o l u t i o n} = \frac{M o l a r m a s s o f u n k n o w n}{m a s s % o f s o l u t i o n}$

$\Rightarrow \frac{342}{5.12} = \frac{x}{0.9} \Rightarrow 60.117$

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