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Question

At certain temperature, a compound AB2 dissociates as: 2AB2(g)2AB(g)+B2(g) with a degree of dissociation α, which is very small compared to unity. The expression of Kp in terms of α and total pressure P is ?


A

α2P2

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B

α2P3

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C

α3P3

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D

α3P2

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Solution

The correct option is D

α3P2


2AB22AB+B2
1α α α2
Total moles =1α+α+α2=2+α2
PAB2=(1α)P(2+α)2=2(1α)P(2+α):PAB=αP(2+α)2=2αP2+α;PB2=α2P(2+α)2=αP2+αHence,KP=P2ABPB2P2AB2=(2αP2+α)2[2(1α)P2+α]2
=α3P2 (α<<1)


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