At constant temperature, a gas is at a pressure of 540 mm of mercury. At what pressure its volume decreases by 60%.

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Solution

$Let the initial volume of gas (V_{1}) = x ∴ The 60 % of initial volume = \frac{60}{100} of x = 0.60 x ∴ The final volume of gas (V_{2}) = x - 0.60 x = 0.40 x The initial pressure of gas (P_{1}) = 540 mm Hg Final pressure of gas (P_{2}) = ? P_{1} V_{1} = P_{2} V_{2} P_{2} = \frac{P_{1} V_{1}}{V_{2}} = \frac{540 \times x}{0.40 x} P_{2} = 1350 mm Hg$

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