Question

At constant temperature, a gas occupies 11.2 liters at 0.860 atm. What is the pressure if the volume becomes 15.0 L?

• A. 0.64

Answer 1

The correct option is A 0.64
According to Boyle's law,
$PV$ = constant
Thus, $P_1{V}_1=P_2{V}_2$

where $P_{1}and{V}_1$ are the initial pressure and volume, and $P_{2}and{V}_2$ are the final pressure and volume of the gas.

Thus, $P_2=\frac{P_1{V}_1}{V_2}$

Hence, $P_2=\frac{0.86X11.2}{15}$
= 0.64 atm