At constant temperature and constant pressure, the heat of the reaction is equal to:
At constant pressure (∆P=0)
Than, Enthalpy
∆H=∆U+∆(PV)
∆H=∆U+P∆V+V∆P; But as (∆P=0)
∆H=∆U+P∆V
But if the Volume is constant (∆V=0)
Than the equation becomes
∆H=∆U+V∆P
What does this Equation implies and what is it's application?