Question

At constant temperature, if pressure increases by 1%, the percentage decrease of volume is

• A. 1%
• B. 100/101%
• C. 1/101%
• D. 1/100%

Answer 1

The correct option is B 100/101%

Let the pressure be denoted by 'p' if the pressure increased by 1% then

$p^1+\frac{p^1}{100}=p$

$P=\frac{101p^1}{100}$

By Boyles law:

PV= constant

$P^1{V}^1=PV$

$P^1{V}^1=\frac{101p^1}{100\times v}$

If we cancel $p^1$ on both sides

$V^1=\frac{101}{100\times V}$

$V=\frac{100V^1}{101}$

If pressure is increased by 1%, volume decreases by 100/101 of its initial volume.

Hence , option B is correct .