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Effect of Change of Temperature on State Change of Matter

at constant v...

Question

at constant volume Gas thermometer using sulphur records pressure of 210 ^4Pascal at triple point of water and 2.87 ten^ 4 pascals at temperature of melting sulphur. calculate the melting point of sulphur.

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Solution

$D e a r S t u d e n t, T r i p l e p o i n t o f w a t e r = T_{t r} = 273.16 K P r e s s u r e a t t h e t r i p l e p o i n t o f w a t e r P_{t r} = 2 \times 10^{4} P a P r e s s u r e a t t h e t e m p r a t u r e o f m e l t i n g s u l p h o r = 2.87 \times 10^{4} P a w e k n o w t h a t \frac{P_{t r}}{P} = \frac{T_{t r}}{T} T h e r e f o r e t e m p r a t u r e o f M e l t i n g s u l p h o r T = \frac{P_{t r}}{P} \times T_{t r} T = \frac{2.87 \times 10^{4} P a}{2 \times 10^{4} P a} \times 273.16 K T = 1.434 \times 273.16 K = 391.98 K R e g a r d s$

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