Question

At constant volume, specific heat of ideal gaseous mixture is $\frac{11}{6}R,$ then the value of adiabatic constant will be

• A. $\frac{17}{6}$
• B. $\frac{7}{3}$
• C. $\frac{11}{6}$
• D. $\frac{17}{11}$

Answer 1

The correct option is D $\frac{17}{11}$

$C_V=\frac{11R}{6}{C}_P=C_V+R=\frac{11R}{6}+R=\frac{17R}{6}\gamma =\frac{C_P}{C_V}=\frac{\frac{17R}{6}}{\frac{11R}{6}}=\frac{17}{11}$