Question

At constant volume the specific heat of a gas is $\frac{3R}{2}$, then the value of $\gamma$ will be

• A. $\frac{3}{2}$
• B. $\frac{5}{2}$
• C. $\frac{5}{3}$
• D. $\frac{4}{3}$

Answer 1

The correct option is C

$\frac{5}{3}$

$C_v=\frac{R}{\gamma -1}\Rightarrow \gamma =\frac{R}{C_v}+1=\frac{5}{3}$