At 27 o C- 4NH 3 g- 5O 2 g- 4NOg- 6H 2 OlGiven- - H-9080J mol -1 and - S-35-7 JK -1 mol -1-The given reaction is spontaneous- non-spontaneous-

Δ G =Δ H TΔ S For the given process, Δ G =9080 300× 35.7= 1630 J mol^ 1 Δ G lt;0 Hence, the given process is spontaneous. ...

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Second Law of Thermodynamics

At 27 o C, ...

Question

At $27^{o} C$ , ${4 N H}_{3} (g) + {5 O}_{2} (g) ⟶ 4 N O (g) + {6 H}_{2} O (l)$

Given, $Δ H = 9080 J {m o l}^{- 1} a n d Δ S = 35.7 {J K}^{- 1} {m o l}^{- 1}$ .

The given reaction is ________( spontaneous/ non-spontaneous).

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Δ H = 35.5 k J {mol}^{- 1}

Δ S = 83.6 k J {mol}^{- 1}

Δ H

Δ S

Δ H = 35.5 k J m o l^{- 1}

Δ S = 83.6 k J m o l^{- 1}

Δ H

Δ S

Δ H = 35.5 k J m o l^{- 1}

Δ S = 83.6 J K^{- 1} m o l^{- 1}

Δ H

Δ S

27^{o} C

Δ H > 0

Δ S > 0

For a reaction $Δ H = 9.08 k J m o l^{- 1}$ and $Δ S = 35.7 J K^{- 1} m o l^{- 1}$ . Which of the following statements is correct for the reaction

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