Question

At equilibrium $500ml$ vessel contains $1.5M$ of each $A,B,C,D$ if $0.5M$ of $C$ and $D$ expelled out than what would be the $K_c$ ?

• A. $1$
• B. $\frac{1}{9}$
• C. $\frac{4}{9}$
• D. $\frac{5}{9}$

Answer 1

The correct option is

A 1

$A+B=C+D$

At equilibrium,$\left[A\right]=\left[B\right]=\left[C\right]=\left[D\right]=1M$

$K=\frac{\left[C\right]\left[D\right]}{\left[A\right]\left[B\right]}$

$K=\frac{1\times 1}{1\times 1}$ =1

On changing the concentrations equilibrium constant does not change.