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Byju's Answer
Standard XII
Chemistry
Kohlrausch Law
At equilibriu...
Question
At equilibrium,
K
p
=
1
, then the value of
Δ
G
o
will equal to:
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Solution
K
.
△
G
=
−
R
T
l
n
k
p
△
G
=
−
R
T
l
n
1
△
G
=
0
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0
Similar questions
Q.
For an equilibrium reaction, if the value of standard Gibb's free energy.
Δ
G
o
is zero, then the value of equilibrium constant,
K
will equal to ?
Q.
At
490
o
C
the value of equilibrium constant,
K
p
is
45.9
the reaction,
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
.
Calculate the value of
Δ
G
o
for the reaction at that temperature?
Q.
The standard Gibbs free energy
Δ
G
o
is related to equilibrium constant
K
P
as:
Q.
If the reaction
A
⇌
B
has
Δ
G
o
=
0
, then its equilibrium constant will be equal to:
Q.
Δ
G
o
for
1
2
N
2
(
g
)
+
3
2
H
2
(
g
)
⇌
N
H
3
(
g
)
is
−
16.5
k
J
m
o
l
−
1
. Find out
K
p
for the reaction at
25
o
C
. Also report
K
p
and
Δ
G
o
for
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
at
25
o
C
.
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