At high temperature of 727∘C, a dynamic equilibrium exists between CO,CO2 and solid carbon. C(s)+CO2(g)⇌2CO(g);KC=0.1M Then value of KP at given temperature is :
A
82.1 atm
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B
0.821 atm
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C
0.0821 atm
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D
8.21 atm
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Solution
The correct option is D 8.21 atm We know from relation between Kp and Kc Kp=Kc(RT)Δn Where, Δn= Number of moles of product in gaseous state - number of moles of reactant in gaseous state (Δn)g=2−1=1
We know,R=0.0821L atm mole −1K−1Temperature (given),T=727∘C=(727+273)K=1000K∴Kp=(0.1)(0.0821×1000)1atm⇒Kp=8.21atm