At high temperature of 727∘C a dynamic equilibrium exists between CO,CO2 and solid carbon. C(s)+CO2(g)⇌2CO(g); Kc=0.1M Then value of Kp at given temperature is:
A
82.1atm
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B
0.821atm
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C
0.0821atm
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D
8.21atm
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Solution
The correct option is D8.21atm Given, Kc=0.1M Temperature,T=727∘C=727+273K=1000K We know, Kp=Kc(RT)(Δn)g The equilibrium given is, C(s)+CO2(g)⇌2CO(g) ∴(Δn)g=2−1=1 Hence, Kp=0.1×0.0821×1000atm Kp=8.21atm