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Conductivity of Ionic Solutions

At infinite d...

Question

At infinite dilution, the equivalent conductance of $C H_{3} C O O N a$ , $H C l$ and $C H_{3} C O O H$ are 91, 426 and 391 $m h o - c m^{2}$ respectively at $25^{\circ} C$ , The equivalent conductance of $N a C l$ at infinite dilution will be:

A

126

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B

209

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C

391

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D

908

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Solution

The correct option is A $126$
$λ_{e q (C H_{3} C O O H)}^{\infty} = λ_{e q (C H_{3} C O O N a)}^{\infty} + \land_{e q (H C l)}^{\infty} - \land_{e q (N a C l)}^{\infty}$

$391 = 91 + 426 - \land_{e q (N a C l)}^{\infty}$

$\land_{e q (N a C l)}^{\infty} = 91 + 426 - 391 = 126 m h o - c m^{2}$

Hence, option A is correct.

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