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Question
At NTP, 1 L of O2 reacts with 3 L of carbon monoxide. What will be the volume of CO and CO2 after the reaction?
At NTP, 1 L of O2 reacts with 3 L of carbon monoxide. What will be the volume of CO and CO2 after the reaction?
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Solution
The correct option is C 2 L CO2, 1 L CO
The chemical reaction is:2CO(g)+O2(g)→2CO2(g) at NTPAccording to Gay Lussac’s Law: In a gaseous system, when the reactants combine together they always do so in volumes which bear a simple ratio to one another and to the volume of the products, under similar conditions of temperature and pressure.
and Avogadro’s Law states that under the same conditions of temperature and pressure, the equal volume of all the gases contains an equal number of molecules/moles.Therefore 1 L O2 will combine with 2 L CO to give 2 L CO2After reaction volume of CO=3−2=1 L and volume of CO2=2 Loption D is correct
The chemical reaction is:
2CO(g)+O2(g)→2CO2(g) at NTP
According to Gay Lussac’s Law: In a gaseous system, when the reactants combine together they always do so in volumes which bear a simple ratio to one another and to the volume of the products, under similar conditions of temperature and pressure.
and Avogadro’s Law states that under the same conditions of temperature and pressure, the equal volume of all the gases contains an equal number of molecules/moles.
Therefore 1 L O2 will combine with 2 L CO to give 2 L CO2
After reaction volume of CO=3−2=1 L and volume of CO2=2 L
option D is correct
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