At NTP, 10 litre of hydrogen sulphide gas reacted with 10 litre of sulphur dioxide gas. The volume of gas, after the reaction is complete, would be:

5 litre

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10 litre

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15 litre

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20 litre

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Solution

The correct option is B 5 litre

$2 H_{2} S + S O 2 \to 2 H_{2} O + 3 S$
According to the equation $2 \times 22.4$ litre of $H_{2} S$ gas reacts with $22.4$ litre of $S O_{2}$
So $5$ litre of $H_{2} S$ reacts with $10$ litre of $S O_{2}$
Hence option $A$ is correct.

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Similar questions

Q. At NTP,

10

liter of hydrogen sulphide gas reacted with

10

liter of suphur dioxide gas. The volume of gas, after the reaction is completed would be:

Q. At STP,

2.8

litres of hydrogen sulphide were mixed with

1.6

litre of sulphur dioxide and the reaction occurred according to the equation:

2 H_{2} S (g) + S O_{2} (g) \to 2 H_{2} O (l) + 3 S (s)

Which of the following shows the volume of the gas remaining after the reaction?

Q. 10 litre of

O_{2}

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Q. At STP , 2.8 litres of hydrogen sulphide were mixed with 1.6 litres of sulphur dioxide and the reaction occurred according to the equation 2H

_{2}

s (g) + SO

_{2}

(g)

\to

_{2}

O(l) + 3S(s)
Which of the following shows the volume of the gas remaining after the reaction?

Hydrogen sulphide gas burns in oxygen to yield 12.8 g of sulphur dioxide gas as under:
$2 H_{2} S + 3 O_{2} \to 2 H_{2} O + 2 S O_{2}$
(i). calculate the volume of hydrogen suulphide at STP.
Also, (ii). calculate the volume of oxygen required at STP. Which will complete the combustion of hydrogen sulphide determined in litres.

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At NTP, 10 litre of hydrogen sulphide gas reacted with 10 litre of sulphur dioxide gas. The volume of gas, after the reaction is complete, would be:

The correct option is B 5 litre 2H2S+SO2→2H2O+3S According to the equation 2×22.4 litre of H2S gas reacts with 22.4 litre of SO2So 5 litre of H2S reacts with 10 litre of SO2Hence option A is correct.

The correct option is B 5 litre

$2 H_{2} S + S O 2 \to 2 H_{2} O + 3 S$
According to the equation $2 \times 22.4$ litre of $H_{2} S$ gas reacts with $22.4$ litre of $S O_{2}$
So $5$ litre of $H_{2} S$ reacts with $10$ litre of $S O_{2}$
Hence option $A$ is correct.