Question

At NTP, density of gas is 0.00045 g/ml. The vapour density & moleculer weight will be :-

Answer 1

The condition at STP are:

$P=1atm$

$T=273.15K$

$R=0.0821Latmmo{l}^{-1}{K}^{-1}$

Given,

$\rho =0.00045g/ml=0.45g/L$

Using the equation, $\rho =\frac{PM}{RT}$

$\Rightarrow M=\frac{\rho RT}{P}$

$\Rightarrow M=\frac{0.45\times 0.0821\times 273.15}{1}$

$\Rightarrow M=10.09$

Since, $VapourDensity=\frac{M}{2}$

$\Rightarrow VapourDensity=5.045$