At NTP, the density of a gas, whose molecular weight is $45$ , is

44.8 g / L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11.4 g / L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 g / L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 g / L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2 g / L$
The density of any substance is calculated as Density = mass / volume.

One mole of any gas at STP will occupy a volume of 22.4 L (standard molar volume). The gas in question would have a molar mass of 45 g/mol.

Therefore, the density of your gas is: D = m/V = 45 g / 22.4 L = 2.0 g/L

Suggest Corrections

Similar questions

The density of a gas is 2 $\frac{g}{L}$ at 1 atm and $27^{0} C$ . The density of the same gas at 2 atm and $127^{0} C$ is:

1.5

2 g / L

300 K

2 a t m

1

0.1784

Join BYJU'S Learning Program