At pH-2- Eoquinhydrone-1-30V- Equinhydrone will be-

The correct option is D 1.42 VFrom E=E^o 0.059/2log[H^+]^2 =1.30 0.059/2log(10^ 2)^2 =1.30+0.236/2=1.418=1.42 V .Hence, the correct option ...

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pH the Power of H

At pH=2, Eo...

Question

At $p H = 2, E_{q u i n h y d r o n e}^{o} = 1.30$ V, $E_{q u i n h y d r o n e}$ will be.

1.36

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1.30

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1.42

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1.20

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p H

E_{Q u i n h y d r o n e}^{\circ} = 1.30 V

E_{Q u i n h y d r o n e}

p H = 2

p H = 2, E_{Q u i n h y d r o n e}

E_{Q u i n h y d r o n e} = 1.30 V)

1 M

Q H_{2} \to Q + 2 H^{+} + 2 e^{-}

Q H_{2}

Q

\frac{2.303 R T}{F} = 0.06

For the half cell $E^{o} = 1.30 V$ . At $p H$ $= 3$ , electrode potential is:

T \propto V^{\frac{- 1}{2}}

γ (C_{p, m} / C_{v, m})

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