At $p H = 2$ , $E_{Q u i n h y d r o n e}$ will be:
( $E_{Q u i h y d r o n e}^{o} = 1.30 V$ )

1.36 V

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1.30 V

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1.42 V

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1.20 V

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Solution

The correct option is A $1.36 V$
Given: $P_{H} = 2$
Given: $E_{0} = 1.30 V P_{H} = - l o g [H^{+ 1}] [H^{+ 1}] = 10^{- 2}$
Applying Nernst Equation,
$E = E_{0} - \frac{0.059}{2} l o g [H^{+ 1}] E = 1.30 - \frac{0.059}{2} l o g [10^{- 2}] E = 1.30 - \frac{0.059}{2} \times (- 2) E = 1.36 V$

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