Question

At $pH=2,E_{\text{Quinhydrone}}$ will be:

Given: $E_{\text{Quinhydrone}}^o=1.30V$

• A. $1.36V$
• B. $1.30V$
• C. $1.42V$
• D. $1.20V$

Answer 1

The correct option is C $1.42V$

For the chemical equation for this reaction is as follows:

$\text{Hydroquinone}\rightleftharpoons \text{Quinone}+2H^{+}+2e^{-}$

Therefore the nernst equation is:

$E=E^0+0.0591pH$

$=1.30+0.0591\times 2$

$=1.418\approx 1.42$

Hence, the correct option is $\text{C}$