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Byju's Answer
Standard VIII
Mathematics
Equation of Circle with Origin as Center
at point P, w...
Question
at point P, which is on the central axis of the circle at distance z from the centre ?
A
0
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B
−
10
Q
4
π
ε
0
√
R
2
+
Z
2
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C
−
2
Q
4
π
ε
0
√
R
2
+
Z
2
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D
−
5
Q
4
π
ε
0
√
R
2
+
Z
2
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Solution
The correct option is
D
−
5
Q
4
π
ε
0
√
R
2
+
Z
2
Point P is equidistant from all the points on the circle.
Potential at P
=
1
4
π
ϵ
−
6
Q
+
Q
√
R
2
+
Z
2
=
1
4
π
ϵ
−
5
Q
√
R
2
+
Z
2
Suggest Corrections
0
Similar questions
Q.
A ring of radius R is having two charges q and 2q distributed on its two half parts. The electric potential at a point on its axis at a distance of
2
√
2
R
from its centre is (
k
=
1
4
π
ε
0
)
Q.
Two concentric thin metallic spheres of radii
R
1
and
R
2
(
R
1
>
R
2
)
bear charges
Q
1
and
Q
2
respectively. Then the potential at a radius r between
R
1
and
R
2
will be
1
/
4
(
π
ε
0
)
times :
Q.
Assertion (A) :
z
1
=
1
+
i
,
z
2
=
1
−
i
then the polar form of
z
1
z
2
is
(
1
,
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2
)
Reason (R) :
z
1
=
(
r
1
,
θ
1
)
,
z
2
=
(
r
2
,
θ
2
)
then
z
1
z
2
is represented as a point in the polar form
(
r
1
r
2
,
θ
1
−
θ
2
)
Q.
If x = r sin θ cos ϕ, y = r sin θ sin ϕ and z = r cos θ, then
(a)
x
2
+
y
2
+
z
2
=
r
2
(b)
x
2
+
y
2
-
z
2
=
r
2
(c)
x
2
-
y
2
+
z
2
=
r
2
(d)
z
2
+
y
2
-
x
2
=
r
2