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Question

At present Ashas the is 2 more than the square of her daughter Nisha age .When Nisha grows to her mother's present age ,Ashas age would be one year less than 10 times he present age if Nisha .Find the present ages of both Asha and Nisha .

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Solution

Let Nisha's age is x years
Aisha's age = (x² + 2) years

Now, A/C to question , when Nisha grows to her mother present age .means Nisha's grows = Aisha's present age - Nisha's present age = x² + 2 - x
Then, this time Aisha's age = Aisha's present age + growing time = x² + 2 + x² + 2 - x = 2x² - x + 4

Now, question said , Aisha's age = 10× times of Nisha's age -1
2x² - x + 4 = 10x -1
2x² - 11x + 5 = 0
2x² -10x - x + 5 = 0
x = 5 and 1/2 x ≠ 1/2 because age doesn't in moths

Hence , Nisha's present age = 5 years
Aisha's present age = (5)² + 2 = 27 years



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