Question

At room temp, $N{H}_3$ gas at one atm &$HCl$ gas at "P" atm are allowed to effuse through identical pin holes to the opposite ends of a glass tube 1 m long & uniform cross-section. A white deposit is observed at a distance of 60 cm; from the $HCl$ end.What is "P"?

Answer 1

$\frac{r_{HCl}}{r_{N{H}_3}}=\frac{P_{HCl}}{P_{N{H}_3}}\sqrt{\frac{M_{N{H}_3}}{M_{HCl}}}$

$\frac{60}{40}=\frac{P}{1}\sqrt{\frac{17}{36.5}}$ or $P=\left[\frac{60}{40}\right]\times \sqrt{\frac{36.5}{17}}$

$=1.5\times 1.465=2.198atm$