Question

At room temperature a diatomic gas is found to have an r.m.s. speed of 1930 $m{s}^{-1}$. The gas is :

• A. $H_2$
• B. $C{l}_2$
• C. $O_2$
• D. $F_2$

Answer 1

The correct option is A $H_2$

Answer is A
WE know that .
$V_{rms}=\sqrt{\frac{3RT}{M}}$
For Hydrogen gas, M $=$ 0.00202 kg/mol
T $=$ 300K, R $=$ 8.314 J mol K
Putting the values, we get
$V_{rms}=1930m/s$
Therefore gas is $H_2$