Question

At room temperature, ammonia gas at one atmosphere pressure and hydrogen chloride at $P$ atmospheric pressure allowed to effuse through identical pinholes from opposite ends of a glass tube of one metre length and uniform section. $N{H}_{4}Cl$ is first formed at a distance of $60cm$ from the end through which $HCl$ gas is sent in. What is the value of?

Answer 1

Using Graham's law of diffusion,

$\frac{r_{HCl}}{r_{N{H}_3}}=\sqrt{\frac{M_{N{H}_3}}{M_{HCl}}}\times \frac{P_{HCl}}{P_{N{H}_3}}$

=$\frac{60}{40}=0.682\times P_{HCl}$

$P_{HCl}=2.198atm$