At room temperature following reaction goes to completion. 2AB(g)+B2(g)→2AB2(g) AB2 is solid with negligible vapour pressure below 0∘C. At 300K, the ABin the smaller flask exerts a pressure of 3atm and the larger flask exerts a pressure of 1atm at 400K when they are separated out by a close valve. The gases are mixed by opening the stop cock and after the end of the reaction the flask are cooled to 250K
A
0.156atm
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B
0.3125atm
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C
0.625atm
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D
3.2atm
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Solution
The correct option is D0.625atm nAB=3×8.210.0821×300=1; nB2=1×8.210.0821×400=0.25 2AB+B2→2AB2 Initial moles 1 0.25 After reaction 0.5 0.5 Pressure of B2PAB×(8.21×8.21)=0.5×0.0821×250=PAB=0.625atm.