Question

At room temperature $H_{2}O$ is a liquid while $H_{2}S$ is a gas. The reason is:

• A. Electronegativity of $O$ is greater than $S$
• B. Difference in the bond angles of both the molecules
• C. Association takes place in $H_{2}O$ due to $H$-bonding while no $H$-bonding in $H_{2}S$
• D. $O$ and $S$ belong to different periods

Answer 1

The correct option is C Association takes place in $H_{2}O$ due to $H$-bonding while no $H$-bonding in $H_{2}S$

Oxygen has small size and high electronegativity because of this, a strong hydrogen bonding is present in $H_{2}O$ which is not found in $H_{2}S.$ Due to this reason, ​at room temperature $H_{2}O$ is a liquid while $H_{2}S$ is a gas.