Question

# At S.T.P a container has 1 mole of $$H_{2}$$, $$2$$ mole $$Ne$$, $$3$$ mole $$O_{2}$$ and $$4$$ mole $$N_{2}$$. Without changing total pressure if $$2$$ mole of $$O_{2}$$ is removed, the partial pressure of $$O_{2}$$ will be decreased by:

A
26%
B
40%
C
58.33%
D
66.66%

Solution

## The correct option is C $$58.33\%$$$$P_{O_{2}}=\dfrac{3}{10}\times P_{T}$$After removing 2 mole of $$O_{2}$$,$$P'_{O_{2}}=\dfrac{1}{8}\times P_{T}$$Decrease in partial pressure of $$O_{2}= \dfrac{\dfrac{3P_{T}}{10}-\dfrac{P_{T}}{8}}{\dfrac{3P_{T}}{10}}\times 100$$                                                                $$= 58.33\%$$Chemistry

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