CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

At S.T.P a container has 1 mole of $$H_{2}$$, $$2$$ mole $$Ne$$, $$3$$ mole $$O_{2}$$ and $$4$$ mole $$N_{2}$$. Without changing total pressure if $$2$$ mole of $$O_{2}$$ is removed, the partial pressure of $$O_{2}$$ will be decreased by:


A
26%
loader
B
40%
loader
C
58.33%
loader
D
66.66%
loader

Solution

The correct option is C $$58.33\%$$
$$P_{O_{2}}=\dfrac{3}{10}\times P_{T}$$

After removing 2 mole of $$O_{2}$$,

$$P'_{O_{2}}=\dfrac{1}{8}\times P_{T}$$

Decrease in partial pressure of $$O_{2}= \dfrac{\dfrac{3P_{T}}{10}-\dfrac{P_{T}}{8}}{\dfrac{3P_{T}}{10}}\times 100$$ 

                                                               $$= 58.33\%$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image