Question

At sea level, the atmospheric pressure is 1.04 $\times {10}^{5}Pa$. Assuming g = 10 $m{s}^{-2}$ and density of air to be uniform and equal to 1.3 kg $m^{-3}$, find the height of the atmosphere.

Answer 1

Atmospheric pressure = $1.04\times {10}^{5}Pa$

g = 10 $m{s}^{-2}$

Density of air = 1.3 kg $m^{-3}$

let height of the atmosphere = h

$P=h\rho g$

$h=\frac{P}{\rho g}$

$h=\frac{1.04\times {10}^5}{1.3\times 10}=8000m=8km$