Question

At sea level, the atmospheric pressure is $1.04\times {10}^{5}Pa$. Assuming $g=10m{s}^{-2}$ and density of air to be uniform and equal to $1.3kg{m}^{-3}$, find the height of the atmosphere.

• A. 8000 km
• B. 8000 mm
• C. 8000 cm
• D. 8000 m

Answer 1

The correct option is D 8000 m

We know that $pressure=\rho \times g\times h$
So, $h=\frac{pressure}{\rho \times g}$
$\Rightarrow h=\frac{1.04\times {10}^5}{10\times 1.3}=8000m$