At some planet ' $g$ ' is $1.96 m / s^{2}$ . If it is safe to jump from a height of $2 m$ on earth, then what should be corresponding safe height for jumping on that planet

5 m

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2 m

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10 m

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20 m

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Solution

The correct option is D $10 m$
At earth, $g_{e} = 9.8 m / s^{2} h_{e} = 2 m$
At other planet, $g_{p} = 1.96 h = ?$
$⟹ \frac{g_{p}}{g_{e}} = \frac{1}{5}$
Now at some planet g reduces by $5$ times, thus safe height will increases by $5$ times.
Hence $h = 5 \times 2 = 10 m$

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