At standard temperature and pressure, the density of a gas is 1.3kgm−3 and the speed of sound in gas is 330ms−1. Then the degree of freedom of the gas will be
A
5
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B
6
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C
7
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D
8
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Solution
The correct option is A5 We know that, v=√γpρ γ=v2pp =(330)2×1.31.015×105=1.4 1+2n=1.4 n=5.