Question

At steady state, the charges (in $\mu C$) on the plates of a capacitor are as shown. The capacitance (in $\mu F$) of the capacitor is

• A. $2$
• B. $4$
• C. $6$
• D. $0$

Answer 1

The correct option is A $2$

As we know that, for calculation of capacitance we take only inner charge on plates.

So, here Q= 24 µC and

V= 12 V (given)

We know that capacitance is given by

C=$\frac{Q}{V}$

C=$\frac{24}{12}$

C=2µF

So, the capacitance on the given capacitor will be 2µF.

So, option (A) is correct.