Question

At $STP$, $10$ grams of a gas occupies $2$ litres. The temperature at which the volume gets doubled, for the same gas at the same pressure is:

• A. $273K$
• B. $-273K$
• C. $546K$
• D. ${546}^{o}C$

Answer 1

The correct option is C $546K$

At a constant pressure, volume is proportional to the absolute temperature.

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Here, $V_1=2$ $L$

$T_1=273K$ ($STP$)

$V_2=4$ $L$

$T_2=??$

Putting all the values, we get $T_2$,

$\frac{2}{273}=\frac{4}{T_2}$

$T_2=546$ $K$

Hence, the correct answer is option $\text{C}$.