At STP, how many liters of O2 can be produced by completely decomposing 2.00 moles of KClO3?
A
11.2
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B
22.4
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C
33.6
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D
44.8
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E
67.2
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Solution
The correct option is C67.2 2KClO3→2KCl+3O2 The decomposition of 2 moles of KClO3 gives 3 moles of oxygen. At STP, one mole of oxygen ocupies a volume of 22.4 L. 3 moles of oxygen will occupy a volume of 3×22.4L=67.2L.