At $S T P$ , the density of a gas (molecular weight 45) in grams per litre is:

2

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22.4

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11.2

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1000

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Solution

The correct option is A $2$
$d = \frac{P M}{R T}$

$d = \frac{45}{0.0821 \times 273}$

Thus, $d = 2 g m / l i t$

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At STP, the density of a gas (molecular weight 45) in grams per litre is:

The correct option is A 2d=PMRTd=450.0821×273Thus, d=2gm/lit

At $S T P$ , the density of a gas (molecular weight 45) in grams per litre is:

The correct option is A $2$
$d = \frac{P M}{R T}$

$d = \frac{45}{0.0821 \times 273}$

Thus, $d = 2 g m / l i t$