At STP, the volume of ammonia formed using 1 mole of nitrogen and 4 moles of hydrogen on complete reaction is:
A
22.4 L
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B
44.8 L
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C
67.2 L
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D
11.2 L
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Solution
The correct option is B 44.8 L The balanced reaction is: N2+3H2→2NH3
Thus, one mole of nitrogen reacts with 3 moles of hydrogen.
We are provided with 1 mole of nitrogen and 4 moles of hydrogen.
Hence, nitrogen is the limiting agent.
Again, 1 mole of nitrogen gives 2 moles of ammonia.
Volume of ammonia formed at STP = 2×22.4 L= 44.8 L