Question

At t = 0, a transverse wave pulse in wire is described by the function;
$y=\frac{6}{x^2+3}$
Where x and y are in meters. Write the function y(x,t) that describes this wave if it travelling in the positive x-direction with a speed of 4.50 m/s.

• A. $y=\frac{12}{\left[\right(x-4.5t{)}^2+3]}$
• B. $y=\frac{6}{\left[\right(x-4.5t{)}^2+9]}$
• C. $y=\frac{16}{\left[\right(x-4.5t{)}^2+3]}$
• D. $y=\frac{6}{\left[\right(x-4.5t{)}^2+3]}$

Answer 1

The correct option is D $y=\frac{6}{\left[\right(x-4.5t{)}^2+3]}$

the equation of transverse wave pulse at $t=o$ is $y=6/(x^2+3)$

since the wave is travelling in positive x direction with speed 4.5 m/s so the position of pulse at t time is $x-4.5\times t$

so the equation of pulse is $y=\frac{6}{(x-4.5t{)}^2+3}$

so the answer is D.