At t = 0, the shape of a travelling pulse is given by $y (x, 0) = \frac{4 \times 10^{- 3}}{8 - (x)^{2}}$ where x and y are in metres. The wave function for the travelling pulse if the velocity of propagation is 5 m/s in the +x direction is given by

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Solution

The correct option is B

$y (x, t) = f (x - v t) y = (x, 0) = \frac{4 \times 10^{- 3}}{8 - (x)^{2}}$

For a travelling wave in the +x – direction

$y (x, t) = \frac{4 \times 10^{- 3}}{8 - (x - 5 t)^{2}}$

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Similar questions

At t = 0, the shape of a travelling pulse is given by $y (x, 0) = \frac{4 \times 10^{- 3}}{8 - (x)^{2}}$ where x and y are in metres. The wave function for the travelling pulse if the velocity of propagation is 5 m/s in the +x direction is given by

Q. At t = 0, a transverse wave pulse in wire is described by the function;

y = \frac{6}{x^{2} + 3}

Where x and y are in meters. Write the function y(x,t) that describes this wave if it travelling in the positive x-direction with a speed of 4.50 m/s.

At t = 0, a transverse wave pulse in a wire is described by the function, $y = \frac{6}{x^{2} + 3}$ where x and y are in metres. Write the function y (x, t) that describes this wave if it is travelling in the positive x-direction with a speed of 4.5 m/s.

Q. A pulse moving along

x -

axis is represented by the wave function

y (x, t) = \frac{2}{(x - 2 t)^{2} + 1}

where

x

and

y

measured in centimeters and

t

is measured in seconds. The shape of pulse

y (x, 0) = \frac{2}{x^{2} + 1}

is shown in the figure below. Which of the following correctly represents the shape of pulse at

t = 1 s

Q. At t = 0, a transverse wave pulse in a wire is described by the function

y = \frac{6}{(x^{2} - 3)}

where x and y are in metres. The function y(x, t) that describes this wave equation if it is travelling in the positive x direction with a speed of 4.5 m/s is

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At t = 0, the shape of a travelling pulse is given by y(x,0)=4×10−38−(x)2 where x and y are in metres. The wave function for the travelling pulse if the velocity of propagation is 5 m/s in the +x direction is given by

The correct option is B y(x,t)=f(x−vt)y=(x,0)=4×10−38−(x)2 For a travelling wave in the +x – direction y(x,t)=4×10−38−(x−5t)2

At t = 0, the shape of a travelling pulse is given by $y (x, 0) = \frac{4 \times 10^{- 3}}{8 - (x)^{2}}$ where x and y are in metres. The wave function for the travelling pulse if the velocity of propagation is 5 m/s in the +x direction is given by

The correct option is B

$y (x, t) = f (x - v t) y = (x, 0) = \frac{4 \times 10^{- 3}}{8 - (x)^{2}}$

For a travelling wave in the +x – direction

$y (x, t) = \frac{4 \times 10^{- 3}}{8 - (x - 5 t)^{2}}$