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Standard XII

Physics

Using Lenz's Law

At t=0, whe...

Question

At $t = 0$ , when the magnetic field is switched on tehe conducting rod is moved to the left at constant speed $5 c m / s$ by some external means. At $t = 2 s$ , net induced emf has magnitude

0.12 V

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0.08 V

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0.04 V

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0.02 V

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Solution

The correct option is B $0.08 V$
At $t = 2 s$ , rod willmove $10 c m$ . Hence $40 c m$ side will become $30 c m$ .
$| e | = e_{1}$ (say) $= S \cdot \frac{d B}{d t}$
$(0.2 \times 0.3) (2) = 0.12 V$
AT $t = 2 s, B = 4 T$
$∴$ $e_{2} = B v l$
$= (4) (5 \times 10^{- 2}) (0.2)$
$= 0.04 V$
$∴$ $e_{n e t} = e_{1} - e_{2} = 0.08 V$

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At t=0, when the magnetic field is switched on tehe conducting rod is moved to the left at constant speed 5cm/s by some external means. At t=2s, net induced emf has magnitude

The correct option is B 0.08VAt t=2s, rod willmove 10cm. Hence 40cm side will become 30cm. |e|=e1 (say) =S⋅dBdt(0.2×0.3)(2)=0.12VAT t=2s,B=4T∴ e2=Bvl=(4)(5×10−2)(0.2)=0.04V∴ enet=e1−e2=0.08V

At $t = 0$ , when the magnetic field is switched on tehe conducting rod is moved to the left at constant speed $5 c m / s$ by some external means. At $t = 2 s$ , net induced emf has magnitude