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Standard XII

Physics

Using Lenz's Law

At t=0, whe...

Question

At $t = 0$ , when the magnetic field is switched on, the conducting rod is moved to the left at a constant speed of $5 c m$ $s^{- 1}$ by some external means. The rod moves perpendicular to the rail. At $t = 2 s$ , induced $e m f$ has magnitude

0.12 V

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0.08 V

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0.04 V

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0.02 V

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Solution

The correct option is A $0.08 V$
Induced emf $e = \frac{d (B A)}{d t} = l_{1} l_{2} \frac{d B}{d t} + l_{2} B \frac{d l_{1}}{d t} = l_{1} l_{2} (2) - l_{2} B v$

At $t = 2 s, l_{1} = 0.4 - 0.5 \times 2 = 0.3, B = 2 (2) = 4$

$e = 0.3 \times 0.2 \times 2 - 0.2 \times 4 \times 0.05 = 0.08 V$

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Similar questions

Q. At

t = 0

, when the magnetic field is switched on tehe conducting rod is moved to the left at constant speed

5 c m / s

by some external means. At

t = 2 s

, net induced emf has magnitude

Q. Figure below shows a conducting rod of negligible resistance that can slide on a smooth U-shaped rail made of a wire of resistance

1 Ω m^{- 1}

. Position of the conducting rod at

t = 0

is shown. A time dependent magnetic field

B = 2 T (tesla)

is switched ON at

t = 0

t = 0

, when the magnetic field is switched ON, the conducting rod is moved to the left at a constant speed of

5 {cms}^{- 1}

by some external means. The rod moves perpendicular to the rail. At

t = 2 s

, induced emf has magnitude

Q. Figure below shows a conducting rod of negligible resistance that can slide on a smooth U-shaped rail made of a wire of resistance

1 Ω m^{- 1}

. Position of the conducting rod at

t = 0

is shown. A time dependent magnetic field

B = 2 T (tesla)

is switched ON at

t = 0

t = 0

, when the magnetic field is switched ON, the conducting rod is moved to the left at a constant speed of

5 {cms}^{- 1}

by some external means. The rod moves perpendicular to the rail. At

t = 2 s

, induced emf has magnitude

Q. At

t = 0

, when the magnetic field is switched on, the conducting rod is moved to the left at a constant speed of

5 c m

s^{- 1}

by some external means. The magnitude of the force required to move the conducting rod at a constant speed of

5 c m

s^{- 1}

at the same instant

t = 2 s

is equal to

Q. Figure shows a conducting rod of negligible resistance that can slide on a smooth U-shaped rail made of wire of resistance 1

Ω m^{- 1}

. Position of the conducting rod at

t = 0

is shown. A time-dependent magnetic field

B = 2 t

(tesla) is switched on at

t = 0

The magnitude of the force required to move the conducting rod at a constant speed of

5 c m / s

at the some intstant of

t = 2 s

is equal to 1000

x \times 10^{- 3} N

, where

x

is (Answer upto 2 decimal places).

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At t=0, when the magnetic field is switched on, the conducting rod is moved to the left at a constant speed of 5 cm s−1 by some external means. The rod moves perpendicular to the rail. At t=2 s, induced emf has magnitude

The correct option is A 0.08 VInduced emf e=d(BA)dt=l1l2dBdt+l2Bdl1dt=l1l2(2)−l2BvAt t=2s,l1=0.4−0.5×2=0.3,B=2(2)=4e=0.3×0.2×2−0.2×4×0.05=0.08V

At $t = 0$ , when the magnetic field is switched on, the conducting rod is moved to the left at a constant speed of $5 c m$ $s^{- 1}$ by some external means. The rod moves perpendicular to the rail. At $t = 2 s$ , induced $e m f$ has magnitude

The correct option is A $0.08 V$
Induced emf $e = \frac{d (B A)}{d t} = l_{1} l_{2} \frac{d B}{d t} + l_{2} B \frac{d l_{1}}{d t} = l_{1} l_{2} (2) - l_{2} B v$

At $t = 2 s, l_{1} = 0.4 - 0.5 \times 2 = 0.3, B = 2 (2) = 4$

$e = 0.3 \times 0.2 \times 2 - 0.2 \times 4 \times 0.05 = 0.08 V$