The correct option is B 2.5 hours
Let the original time be T hours and the original speed be S km/hr.
So, distance = S × T km (1)
As there is a decrease in speed by 20%, so new speed = S × 80% =45S
Also, the increase in time is 30 minutes=12 hour
So, new time=(T+12)hours
Now distance,D=45S×(T+12)(2)
On equating (1) and (2), we get
S×T=45S×(T+12)
⇒ 5T = 4T + 2
⇒ T = 2 hours
Actual time taken = 2 hours + 30 minutes = 2.5 hours
Hence, option B is the correct answer.
Alternatively:
If the speed is decreased by 20%, then the time taken to cover a certain distance will increase by 25%.
So, if the original time taken is 4x, then the actual time taken will be 5x.
Now, 5x – 4x = 30 minutes
So, x = 30 minutes
Thus, actual time taken = 5x = 150 minutes = 2.5 hours.
Hence, option B is the correct answer.