Question

At the Earth, a block of mass $m$ which rest on the frictionless table, let $F$ be the force required to produce acceleration $a$. Calculate the force at the Moon to produce same acceleration if $g_{moon}$ is one sixth of $g_{earth}$.

• A. $\frac{F}{12}$
• B. $\frac{F}{6}$
• C. $\frac{F}{3}$
• D. $F$
• E. $6F$

Answer 1

Answer: (D)

$F$

The force required to accelerate the block by $a$:

$F=ma$ which is independent of the value of gravitational force acting on the block vertically downwards.