At the first minima, adjacent to the central maxima of a single - slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

\frac{π}{8}

radian

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\frac{π}{4}

radian

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\frac{π}{2}

radian

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π

radian

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Solution

The correct option is D $π$ radian

$F o r f i r s t m i n i m a a t P, a sin θ = λ S o, p h a s e d i f f e r e n c e Δ ϕ_{1} = \frac{Δ x_{1}}{λ} \times 2 π = \frac{(a / 2) sin θ}{λ} \times 2 π Δ ϕ_{1} = \frac{λ}{2 λ} \times 2 π = π r a d i a n$

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At the first minima, adjacent to the central maxima of a single - slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

The correct option is D π radian For first minima at P,a sin θ = λSo, phase differenceΔϕ1=Δx1λ×2π =(a/2)sin θλ×2πΔϕ1=λ2λ×2π = π radian

The correct option is D $π$ radian

$F o r f i r s t m i n i m a a t P, a sin θ = λ S o, p h a s e d i f f e r e n c e Δ ϕ_{1} = \frac{Δ x_{1}}{λ} \times 2 π = \frac{(a / 2) sin θ}{λ} \times 2 π Δ ϕ_{1} = \frac{λ}{2 λ} \times 2 π = π r a d i a n$