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Question


At the limit state of collapse, an RC beam is subjected to flexural moment 200 kN-m, shear force 20 kN and torque 9 kN-m. The beam is 300 mm wide and has a gross depth of 425 mm, with an effective cover of 25 mm. The equivalent nominal shear stress (τve) as calculated by using the design code turns out to be lesser than the design shear strength (τc) of the concrete.

The equivalent shear force (Ve) is

A
20 kN
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B
54 kN
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C
56 kN
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D
68 kN
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Solution

The correct option is D 68 kN
Flexural moment,
M = 200 kN-m
Shear Force, V = 20 kN
Torque, T = 9 kNm
Width, B = 0.3 m
Depth, D = 0.425 m
Equivalent shear force

Ve=V+1.6 TB=20+1.6×90.3=68 kN

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