Question

At the moment t = 0 particle leaves origin and moves in the positive direction of x-axis. Its velocity as a function of time is given as v = (5-t) m/s. x-coordinate of particle at t = 2 sec is

• A. 8 m
• B. 6 m
• C. 10 m
• D. 12 m

Answer 1

The correct option is A 8 m

$v=\frac{dx}{dt}=(5-t)\Rightarrow {\int }_0^{x}dx={\int }_0^2(5-t)dt$
$x=[5t-\frac{t^2}{2}{]}_0^2\Rightarrow x=5\times 2-\frac{2^2}{2}=8m$