At the same temperature and pressure the rates of diffusion of gases are inversely proportional to the:

M o l . W t .

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M o l . W t . / 2

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\sqrt{M o l . W t .}

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M o l . W t . / 3

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Solution

The correct option is C $\sqrt{M o l . W t .}$
According to Graham's law of diffusion,
$r a t e \propto \frac{1}{\sqrt{M o l e c u l a r w e i g h t}}$
$\frac{{r a t e}_{1}}{{r a t e}_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$
The rate of effusion or diffusion of gas is inversely proportional to the square root of the mass of its particle.

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At the same temperature and pressure the rates of diffusion of gases are inversely proportional to the:

The correct option is C √Mol.Wt.According to Graham's law of diffusion,rate∝1√Molecularweightrate1rate2=√M2M1The rate of effusion or diffusion of gas is inversely proportional to the square root of the mass of its particle.